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RE: Orbital velocity question
That's it !! Well done John. I see you were staring at it longer than I. HI
HI
I've printed it off so I can keep it - I knew it was the correct equation, I
just couldn't quite get to it.
Thanks for your expertise !
73, Jamie
WB4YDL
_____
From: John Henderson [mailto:jah@ec.rr.com]
Sent: Monday, May 30, 2005 7:35 PM
To: 'James C. Hall, MD'
Cc: AMSAT-BB
Subject: RE: [amsat-bb] Orbital velocity question
Jamie,
I finally derived the equation in the Journal and it is correct.
Hope I can type this clearly....
The balancing force on a satellite at distance r is:
(GMm)/r**2 = mw**2r
G = gravity at surface, M = Earth mass m=sat mass r=distance from center
of Earth w= angular velocity of sat
The Orbital Velocity found from using the above and orb velocity :
v = rw and g = GM/R**2 where g is gravity at sat and R is earth radius.
Solving the forced equation for wr we get SqRT(GM/r) =wr
Therefore v = SqRT (GM/R); solve g=GM/R**2 for GM we get g(R**2)
Substitute in v= SqRT (GM/r) GM=g(R**2) and you get:
V = SqRT (( gR**2)/r)
73, John
N4NAB/ FM14lq
AMSAT # 32411
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