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RE: Orbital velocity question



Hi John:

First, has anybody else but me noticed that it takes a long time for
messages to post to the amsat-bb ? Hours for me.

Anyway, yes, I understand that if you set kinetic energy to the work to
defeat gravity (the first integral of gravitational force), that you can
arrive at the escape velocity. 

My problem in the text of Gould's article was how exactly he came to have
R^2/r in his equation. I'm close, but it just seems that the two (R & r)were
interposed in the last step. I'll figure it out sometime. I'm giving a talk
to our ham club in August on satellite communications, and I've trying to do
some homework. :)

BTW, that was a nice web site you sent which I have bookmarked.

73, Jamie
WB4YDL

-----Original Message-----
From: owner-AMSAT-BB@amsat.org [mailto:owner-AMSAT-BB@amsat.org] On Behalf
Of John Henderson
Sent: Monday, May 30, 2005 3:30 PM
To: 'James C. Hall, MD'
Cc: AMSAT-BB
Subject: RE: [amsat-bb] Orbital velocity question

Jamie,
 
 Take a look at 
 
http://www.syvum.com/physics/gravitation/gravitation3.html
 
The formula in the text, I believe ,is orbital velocity, not escape
velocity.
 
Escape velocity is v= v2gR
 
 
 
 
 
 
 
73,  John 
N4NAB/ FM14lq
AMSAT # 32411
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