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*Subject*: [amsat-bb] Orbital velocity question*From*: "James C. Hall, MD" <heartdoc@xxxxxxxxx>*Date*: Sun, 29 May 2005 18:21:34 -0500*Thread-index*: AcVkpSb2KWWoAmyWTSWgHbAoOajt9Q==

Hello all: I've been out of Physics for some time, but while reviewing Gould Smith's excellent article on orbital basics in the Jan/Feb issue of the AMSAT journal, I was confused as to the derivation of the orbital velocity equation. I've fooled with it for a few hours but I can't seem to figure out the R^2/r factor in the equation. I understand that the acceleration due to gravity is less at the orbital height and that, due to conservation of angular momentum, v`r = vR (where v` is the orbital velocity), but when I square both sides and divide by r^2, I get stuck . because g = v^2/R, not v^2/r. So I can't get the v`^2 = g R^2/r. I'm missing something . I know, I know . it's been a slow day !! 73, Jamie WB4YDL ---- Sent via amsat-bb@amsat.org. Opinions expressed are those of the author. Not an AMSAT member? Join now to support the amateur satellite program! To unsubscribe, send "unsubscribe amsat-bb" to Majordomo@amsat.org

**Follow-Ups**:**RE: Orbital velocity question***From:*John Henderson

**RE: Orbital velocity question***From:*John Henderson

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