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*Subject*: RE: [amsat-bb] AO40 velocity*From*: Robert McGwier <rwmcgwier@xxxxxxxxxxx>*Date*: Thu, 29 Aug 2002 18:12:09 -0400*In-reply-to*: <20020829.112646.-144325.2.W7LRD@juno.com>

Bob: The Vis-viva equation is what you are looking for I think. V^2 = mu (2/r - 1/a) where r is the distance of the satellite from earth center and a is the semimajor axis. mu varies according to the units you use. If the units are in earth radii, then mu is 1 and the velocity squared is given in (earth radii per second)^2. You take the square root of this to get velocity. If you measure the distances in meters, I believe mu is approximately 1501416 if I did the conversion correctly! Bob N4HY -----Original Message----- From: owner-AMSAT-BB@AMSAT.Org [mailto:owner-AMSAT-BB@AMSAT.Org]On Behalf Of Bob V Johnson Sent: Thursday, August 29, 2002 2:27 PM To: amsat-bb@AMSAT.Org Subject: [amsat-bb] AO40 velocity Hello I was asked how fast "those things" go. I took a guess and probably was fairly correct. That got me thinking how fast really is it. Given the MA, at that part of the orbit is there a formula that would yield the velocity at that point? 73...Bob...W7LRD Seattle, Wa. "everything is a learning curve" ---- Via the amsat-bb mailing list at AMSAT.ORG courtesy of AMSAT-NA. To unsubscribe, send "unsubscribe amsat-bb" to Majordomo@amsat.org ---- Via the amsat-bb mailing list at AMSAT.ORG courtesy of AMSAT-NA. To unsubscribe, send "unsubscribe amsat-bb" to Majordomo@amsat.org

**References**:**AO40 velocity***From:*Bob V Johnson

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