# Re: ultiment squint profile

• Subject: Re: [amsat-bb] ultiment squint profile
• From: "Ib Christoffersen" <oz1my@xxxxxxxxx>
• Date: Sun, 25 Nov 2001 10:07:13 +0100

```Hi Joseph and all,
I asked Viktor Kudielka a similar question some time ago.

The answer, as I remember it, is that the difference in squint
angle in the footprint, when AO-40 is at or near apogee is
approximately 5 degrees.

One way to test this - if you use NOVA f. Windows - is to
make AO-40 earth pointing. Make a couple of test runs and
use listing to get the squint angle.

73 OZ1MY/Ib

----- Original Message -----
From: "joseph Murray" <k0vty@juno.com>
Sent: Saturday, November 24, 2001 10:53 PM
Subject: Re: [amsat-bb] ultiment squint profile

> Hi Gunther
>
> AO-40 questions :
>
> Do we know what the actual Sub Satellite Point will be under inertial
> wheel stabilization?
> Does the Stabilization point on the surface of the earth have to be on a
> line which between the center of the earthy and the satellite position"
> How much dynamics are involved in the stability of that pointing ( not at
> perigee )
> Folks with higher fixed latitudes North or South of the equator would I
> am sure like to have a means to calculate their predicted squint angle,
> horizon to horizon for a given satellite pass.
>
> Thanks for bringing the subject to the BB
>
> Joe  K0VTY
> ========================
> On Sat, 24 Nov 2001 18:13:02 -0500 "Gunther Meisse"
> > Attention Math and orbital gurus!
> > For planning purposes:
> > When AO-40 in in total inertia wheel stabilization, what will the
> > worst case
> > squint window (east to west) of the satellite sub-point? To simplify
> > the
> > issue: the question is at 42 degrees North.
> > Thank you for your assistance.
> > 73
> > Gunther Meisse
> > W8GSM
> > AMSAT LM: 594
> >
> >
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> >
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