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# Re: School days on Oscar 27 - 28 January

• Subject: Re: [amsat-bb] School days on Oscar 27 - 28 January
• From: "KF4FDJ (Mike in Fort Myers, FL)" <seven77@xxxxxxxx>
• Date: Wed, 27 Jan 1999 21:44:42 -0500

```Thanks Randy, Stacey, Jeff,

for taking the time to answer my question.  I plan to do a short lecture on
doppler and wanted to know how fast the bird is moving.  I hope to get the kids
as involved as possible.  It will no doubt be much different than the typical
hamfest demos I've been doing.

73, Mike kf4fdj@amsat.org

Stacey Mills wrote:

> At 03:29 PM 1/27/99 -0500, you wrote:
> >
> >P.S.  Who knows how fast AO27 travels?  Let me know if you know the
> >answer.
>
> AO-27's perigee = 774 km, apogee = 787 km
> Assume orbit is circular at 780.5 km.
> Earth's mean orbital radius = 6367 km.
> therefore one orbit on AO-27 = (6367+780.5)*2*PI = 44,909 km./orbit
>
> AO-27's mean motion = 14.278 orbit/day
> 24hr/14.278 = 1.68 hrs/orbit
>
> 44,909 km/orbit / 1.68 hrs/orbit = 26,731 km/hr
> --or--
> 26,731 km/hr * 0.621 mi/km =  16,600 mi/hr (give or take)
>
> --
>  __________________________________________________________________________
>   Stacey E. Mills, W4SM    WWW:         http://www.cstone.net/~w4sm/ham1.html
>    Charlottesville, VA     PGP key:     http://www.cstone.net/~w4sm/key.asc
>  __________________________________________________________________________
>
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