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Re: School days on Oscar 27 - 28 January



On Wed, 27 Jan 1999 20:16:50 -0500, w4sm@cstone.net (Stacey Mills) wrote:

> AO-27's perigee = 774 km, apogee = 787 km
> Assume orbit is circular at 780.5 km.
> Earth's mean orbital radius = 6367 km.
> therefore one orbit on AO-27 = (6367+780.5)*2*PI = 44,909 km./orbit
> 
> AO-27's mean motion = 14.278 orbit/day
> 24hr/14.278 = 1.68 hrs/orbit
> 
> 44,909 km/orbit / 1.68 hrs/orbit = 26,731 km/hr 
> --or--
> 26,731 km/hr * 0.621 mi/km =  16,600 mi/hr (give or take)

Cool, astrophysics! Everyday amateur radio seems to teach me something that
broadens my horizons. I love it!

73 Jeff W4JEF

    *=-=-=-=-=-=-=-=-= Jeff Johns W4JEF - AMSAT# 32615 -=-=-=-=-=-=-=-=*
    |jeffj@scott.net  w4jef@amsat.org |     Reserve Patrol Captain     |
    |  Satellite: Mir R0MIR-1, AO-27  | Jefferson County Sheriff's Dept|
    |200LX+BayPac+FT50=Portable Packet|     QTH Birmingham, AL USA     |
    *=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-=-*


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