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*Subject*: Re: [amsat-bb] [Fwd: Fw: Freaky Formula]*From*: "Kenneth J. Ernandes" <n2wwd@xxxxxxxxxxxxxx>*Date*: Tue, 07 Jul 1998 18:58:57 -0400

The formula is not at all freaky. 1. Multiplying the number in step #1 by two and then later by 50 is the same as multiplying it by 100 -- hence the first digit. 2. Multiplying 5 by 50 and is 250. Adding 1748 to 250 is 1998 (this year) if you've already had your birthday. If you haven't had your birthday, then he year of your last birthday is 1997 = 250 + 1747. 3. Subtracting your birth year from the year of your last birthday will give your age -- hence the last two digits. BTW, the formula will work next year if you use 1749 instead of 1748 and 1748 instead of 1747 in step #5. Is it obvious in hindsight? 73, Ken N2WWD n2wwd@amsat.org http://www.mindspring.com/~n2wwd At 15:30 7/7/98 -0400, you wrote: >>This really works...try it...Have a great 4th of July. >>>IT REALLY WORKS. DON'T CHEAT BY SCROLLING DOWN FIRST!!! >>>It only takes 30 seconds so work this out as you read. >>>Don't read the bottom until you have worked it out!!! >>> >>>1. First of all, pick the number of days a week that you would like >>> to go out for dinner. >>> >>>2. Multiply this number by 2. >>> >>>3. Add 5. >>> >>>4. Multiply it by 50. >>> >>>5. If you have already had your birthday this year, add 1748. >>> If you haven't, add 1747. >>> >>>6. Last step: Subtract the four digit year that you were born >>> (e.g. 1958). see below: >>> >>> >>> >>>RESULTS: >>> >>>You should now have a three digit number: >>> >>>The first digit of this was your original number (i.e. how many times you >>>want >>>to go out each week). >>> >>>The second two digits are your age!!! >>> >>>Freaky, huh? >>>. >>>This is the only year it will ever work, > >>> >>> >>> >>> >>> >>> >> > Ken Ernandes n2wwd@amsat.org http://www.mindspring.com/~n2wwd ---- Via the amsat-bb mailing list at AMSAT.ORG courtesy of AMSAT-NA. To unsubscribe, send "unsubscribe amsat-bb" to Majordomo@amsat.org

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